//判断负环 在负环内的城市输出?
#include <iostream>
#include <queue>
#include <cstdio>
#include <algorithm>
#include <string.h>
#include <string>
using namespace std;
typedef long long LL;
const int N=4e5+;
int abc[];
int T,n,m,q;
int h[N],e[N],ne[N],w[N],idx;
int len(int u,int v){
return (abc[v]-abc[u])*(abc[v]-abc[u])*(abc[v]-abc[u]);
}
void add(int a,int b)
{
e[idx]=b;
w[idx]=len(a,b);
ne[idx]=h[a];
h[a]=idx++;
}
int dist[],st[],times[],cycle[];
void spfa()
{
memset(dist,,sizeof(dist));
memset(st,,sizeof(st));
memset(times,,sizeof(times));
memset(cycle,,sizeof(cycle));
queue<int>q;
st[]=times[]=;
dist[]=;
q.push();
while(q.size())
{
int u=q.front();
q.pop();
st[u]=;
for(int i=h[u];~i;i=ne[i])
{
int v=e[i];
if(cycle[v])
continue;
if(dist[v]-dist[u]>w[i])
{
dist[v]=dist[u]+w[i];
if(!st[v])
{
st[v]=;
times[v]++;
q.push(v);
}
if(times[v]>n)
cycle[v]=;
}
}
}
}
int main()
{
cin>>T;
for(int t=;t<=T;t++)
{
idx=;
memset(h,-,sizeof h);
cin>>n;
for(int i=;i<=n;i++)
cin>>abc[i];
cin>>m;
int a,b;
while(m--)
{
cin>>a>>b;
add(a,b);
}
spfa();
cin>>q;
printf("Case %d:\n",t);
while(q--)
{
cin>>a;
if(dist[a]<||dist[a]>=(int)1e9||cycle[a])
printf("?\n");
else
printf("%d\n",dist[a]);
}
}
}
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